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4a^2-51=0
a = 4; b = 0; c = -51;
Δ = b2-4ac
Δ = 02-4·4·(-51)
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{51}}{2*4}=\frac{0-4\sqrt{51}}{8} =-\frac{4\sqrt{51}}{8} =-\frac{\sqrt{51}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{51}}{2*4}=\frac{0+4\sqrt{51}}{8} =\frac{4\sqrt{51}}{8} =\frac{\sqrt{51}}{2} $
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